Refinement lvl Chance of success Compund probability BE needed BE returned for failure
1.................................100.00%......................100.00%..................0.............................0 2.................................100.00%......................100.00%..................0.............................0 3..................................90.00%........................90.00%..................1.............................0 4..................................80.00%........................72.00%..................2.............................1 5..................................80.00%........................57.60%..................4.............................2
6..................................70.00%........................40.32%..................7.............................3 7..................................50.00%.........................20.16%..................10...........................4 8..................................40.00%..........................8.06%..................15...........................5 9..................................40.00%..........................3.23%..................20...........................6
Adapted from
http://phpbb.acclaim.com/9dragons/viewtopic.php?t=85639&postdays=0&postorder=asc&highlight=reece&start=15
This post shall be fairly technical, but I hope it will be of help to those who read it.
Expected Cost of A Refined Weapon
I shall first draw up a general formula for calculating the price associated with a weapon of a particular refinement level:
You go to the refiner with your weapon, the refinement material and pay some gold, and there are 2 possible outcomes:
1. You get a weapon of the next refinement level with chance c.
2. You fail and get some BE returned, if any, with a chance (1-c).
Let W be the price of the unrefined weapon,
and B be the price of BE,
M(n) be the number of BE associated with the material required to refine from n to n+1,
Br(n+1) be the number of BE returned upon failure in refining from n to n+1,
Pr(n) be the expected cost of a weapon of a particular refinement level
and R(n) be the amount of gold you have to pay to the refiner to refine it from n to n+1.
Pr(n) + R(n)+ M(n) = cPr(n+1) + (1-c)Br(n+1)
Rearranging, we derive a recursive formula for calculating the expected cost associated with a weapon of refinement n+1.
Pr(n+1) = 1/c[Pr(n) + R(n) + M(n) - (1-c)Br(n+1)]
Pr(1) = W + 1100 + 1000 = W +2100
Pr(2) = Pr(1) + 3300 + 3000 = W + 8400
Pr(3) = 1/0.9[Pr(2) + 5000 + B] = 1.11W + 14889 + 1.11B
Pr(4) = 1/0.8[Pr(3) + 10000 + 2B - 0.2B] = 1.39W+ 31111 + 3.64B
Pr(5) = 1/0.8[Pr(4) + 20000 + 4B - 0.4B] = 1.74W + 63889 + 9.05B
Pr(6) = 1/0.7[Pr(5) + 35000 + 7B - 0.9B] = 2.48W + 141270 + 21.64B
Pr(7) = 1/0.5[Pr(6) + 50000 + 10B - 2B] = 4.96W + 382540 + 59.28B
Pr(8) = 1/0.4[Pr(7) + 75000 + 15B - 3B] = 12.40W + 1143849 + 178.20B
Pr(9) = 1/0.4[Pr(8) + 100000 + 20B - 3.6B] = 31.00W + 3109623 + 486.51B
Interpreting the Results
By looking at the coefficient of W, you can find out how many weapons on average it will take in order to refine a weapon from +0 to +n. You can also find out how many weapons on average it will take you to refine from +n to +(n+k) by dividing the coefficient of W for line Pr(n+k) by the coefficient of W for line Pr(n).
By looking at the coefficient of B, you can find out how many BEs on average it will take in order to refine a weapon from +0 to +n.
Buying vs Refining
As shown from the results of the calculation, the cost associated with refining a weapon can become amazingly high at the higher refinement levels, it more than doubles from one refinement level to the next (assuming you are refining a normal weapon).
When deciding whether it worthwhile to buy a weapon from a stand, simply refer to the above results and substitute appropriate values for the variables. Chances are, it is better to buy than refine a weapon. The above results can be also used as a tool for comparing two weapons of the same type of different refinement levels. For example, you might find a +5 weapon at price x and a +6 weapon of the same type at price x+c. By using the line Pr(6), substituting Pr(5) with x and using a suitable value for B, you can determine if it would be better for you to get the +5 weapon and refine it to +6 or to buy that +6 weapon.
If you decide to refine a weapon, you can be sure that you will not be able to recover the value associated with a refined weapon of that level - that is, the price you can expect to receive from selling a refined weapon will be lower than the expected cost in refining it to that level, Pr(n). Take a +9 weapon for example, you will never be able to get a price of 487BE for it. Hence, if you are concerned about breaking even, you should exercise great caution when it comes to refining - the odds are greatly weighted against you, not just by the probabilities of success, but also by market forces.
I hope this post has provided with a rigorous basis for your decision as to whether to refine a weapon or otherwise. Take your time with the math, and weigh for yourself the risks against the potential gain.
6 comments
Yeah. 49BE for a level 9 wep, with a 3-4% chance of success. I've had weps vanish at +3.
I guess we know how the internal economy of the game could be collapsed. Increasing the success rate of refinement would increase the demand for BE over the very short term, but shortly after that the demand would collapse along with the price of everything in the game.
for me its better to buy ref weapon, and i think this is better for everyone, but then who would ref weapons?
there are many people that refine weapons beacause they think they will get it +9. but whn they get it +5 they won't try anymore because they will think that they have a low chance of succes. btw a friend of mine made a saber +9 GB 1 or 2 with just 1 try
Yeah well, I lost a pretty good HP return spear at +3 and recently two other weapons at +5 and +6.
lot's of ecuation and u need to know math really well to estimate that succes chances very nice post (it took me about 15mins to understand all of it)
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